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Apr 16, 14 · The first step is to state that S 1 = 1 – 1 1 – 1 1 – 1 = 1/2 Step 2 if S 2 = then 2S 2 = 1 2345 1234 Here we have "shifted along by one space" the second S 2 This means that when we add the two sequences together we end up with 2S 2 = = 1/2 which gives S 2 = 1/4 Step 3 Do S – S 2 = 1 2 3 4 5 (1 – 2 3 – 4 5) = 4 8Mar 18, 14 · So on the left side use only the (2n1) part and substitute 1 for n On the right side, plug in 1 They should both equal 1 Then assume that k is part of the sequence And replace the n with k Then solve for k1 k1 135 (2k1) (2k1)=k^22k1 The right hand side simplifies to (k1)^2 2 commentsObserving that a = b b b = b {\displaystyle bb=b} Combine like terms on the left 2 b = b {\displaystyle 2b=b} Divide by the nonzero b 2 = 1 {\displaystyle 2=1} QED The fallacy is in line 5 the progression from line 4 to line 5 involves division by a − b, which is zero since a = b Algebra Sleuth Proof That 1 2 Activity Education Com Mathematical proof of 1+1=2 pd...